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Jan 29, 19 · E X = np Σ r = 0 n – 1 C(n – 1, r) p r (1 – p) (n – 1) r By the binomial formula, (x y) k = Σ r = 0 k C( k, r)x r y k – r the summation above can be rewritten E X = (np) (p (1 – p)) n – 1 = np The above argument has taken us a long way From beginning only with the definition of expected value and probability massEZO C _ n E X Ńv ` 򗷋C E q 쓒 ɂ EZO C _ n E X B { w ̍L ȋ ΘH J f ɂ́A ΁A ΘH ΁A R B p X b g ̊ό n Ɍb ܂ꂽ ō ̃ P V BFundamental Theorem of Calculus Solve x ^(n1) dx Let E 1 X In R X Ne 1 And X X 1 Gt 0 And E 2 X In E 1 N c l e x

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